Doesn't work for strings with length 1

[taylorjacklespriggs]

This looks like expected behavior, but it could be useful to fall back to a simple algorithm if one of the inputs is a length 1 string.

  if (first.length === 1 || second.length === 1) {			           // if either is a 1-letter string
    let [smaller, larger] = (first.length === 1)
      ? [first, second]
      : [second, first];
    return larger.includes(smaller) ? 2.0 / (larger.length + 1) : 0;
  }

This came up when I tried to use compareTwoStrings for a search ranking.

string-similarity/compare-strings.js

Line 14 in ccdb537

if (first.length < 2 || second.length < 2) return 0; // if either is a 1-letter string

[jechazelle]

Hello @taylorjacklespriggs, did you found a solution ?